根据cURL响应创建许多变量-Bash

由 mex发布于 2020-04-03 09:50:24

Let's assume, I have this package jq installed. So I ran this command

curl -s ipinfo.io/33.62.137.111

得到这个结果

{
  "ip": "33.62.137.111",
  "city": "Columbus",
  "region": "Ohio",
  "country": "US",
  "loc": "39.9690,-83.0114",
  "postal": "43218",
  "timezone": "America/New_York",
  "readme": "https://ipinfo.io/missingauth"
}

I know I can get city by doing this

curl -s ipinfo.io/33.62.137.111 | jq -r'.city'

I know I can get region by doing this

curl -s ipinfo.io/33.62.137.111 | jq -r'。区域'

我试图卷曲7次以创建7个变量。

是否可以根据第一个curl响应创建多个变量？

DJHongKong

2020-04-03 09:50:24

使用关联数组使用Bash 4+可以轻松实现：

#!/usr/bin/env bash

# Map the JSON response into an associative array
declare -A "assoc_array=($(
  curl -s ipinfo.io/33.62.137.111 | jq -r 'to_entries[] | "[\(.key | @sh)]=\(.value | @sh)"'
))"
IFS=, read -r assoc_array[lat] assoc_array[long] <<<"${assoc_array[loc]}"

echo "Here is how assoc_array was declared/created"
echo
typeset -p assoc_array
echo
echo
# Display the content of the associative array

echo "Here is a breakdown of all entries in the assoc_array:"
echo
for k in "${!assoc_array[@]}"; do
  printf '%q = %q\n' "$k" "${assoc_array[$k]}"
done

样本输出：

Here is how assoc_array was declared/created

declare -A assoc_array=([country]="US" [region]="Ohio" [city]="Columbus" [timezone]="America/New_York" [ip]="33.62.137.111" [lat]="39.9690" [readme]="https://ipinfo.io/missingauth" [long]="-83.0114" [loc]="39.9690,-83.0114" [postal]="43218" )


Here is a breakdown of all entries in the assoc_array:

country = US
region = Ohio
city = Columbus
timezone = America/New_York
ip = 33.62.137.111
lat = 39.9690
readme = https://ipinfo.io/missingauth
long = -83.0114
loc = 39.9690\,-83.0114
postal = 43218

mex

这家伙很懒，什么都没留下

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