Python Discord Bot如何将消息与列表进行比较

由深蓝Xx发布于 2020-05-09 06:14:22

我正在制作一个python Discord Bot，现在我正试图使他响应列表中的特定消息，但是存在一些问题，因为他仅在消息开始时才响应（不在中间或结尾）。所以我想弄清楚如何让他比较所有文本并与消息列表匹配，发送文本答案。

Python 3.8.2

码：

import discord
from discord.ext        import commands
from discord.ext.commands   import Bot
import asyncio

bot = commands.Bot(command_prefix = "$")
phrases = ["QWACK","KWAK","AARK","KWAAAK"]

@bot.event
async def on_ready():
    print ("I'm ready!")

@bot.event
async def on_message(message):
    if str(phrases) in message.content:                                                    
        await message.channel.send("dhbang")

Doyle

2020-05-09 06:14:23

我很惊讶机器人对所有xD都做出了回应

str（phrases）是一个字符串，这个特定的字符串：“ [” QUACK“，” KWAK“，” AARK“，” KWAK“]”

您应该遍历每个单词，并检查该单词是否在消息中。

您还应考虑大写字母和在一条消息中出现多个关键字。

蹦叉叉

2020-05-09 06:14:23

As wrong1man said, str(phrases) is a string, so it should only respond to messages like Lovely day, isn't it ["QWACK","KWAK","AARK","KWAAAK"]?. I would just like to extend wrong1man's answer by giving some code:

if any((phrase in message.content) for phrase in phrases):                                                    
    await message.channel.send("dhbang")

The above is the more concise version using a generator expression. If you are a Python begginer, you may be more comfortable with a normal for loop:

for phrase in phrases:
    if phrase in message.content:                                                    
        await message.channel.send("dhbang")
        break

深蓝Xx

这家伙很懒，什么都没留下

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