我需要从...更改这样的图像
https://www.website.com/images/stuff/95/jgfij/public/2019/09/cow.gif
https://www.website.com/images/stuff/df3/4gy0/public/2015/03/horse.png
https://www.website.com/images/stuff/odpk/f049/public/2020/08/dog.jpg
进入...
https://www.website.com/images/stuff/public/2019/09/cow.gif
https://www.website.com/images/stuff/public/2015/03/horse.png
https://www.website.com/images/stuff/public/2020/08/dog.jpg
我试过了但是没用
document.body.innerHTML = document.body.innerHTML.replace('https://www.website.com/images/stuff/*/public/,'https://www.website.com/images/stuff/public/');
我一直在尝试寻找可以删除网址的特定部分之间的所有内容的工具，但我从没有碰过运气。
您的示例可能不是您想要的。可能是以下情况：
You were missing an endquote on the regex, and had
/*, which means "zero or more slashes" when you probably want.*, "zero or more of any character".