I really need your help and I know It is easy to you. I made the following code to show a modal bootstrap by loading every page of my website. but I need to show that modal just for 3 times to every user. so I need to count times the user click on the button to close modal. If the user 3 times has closed the modal, I do not want to show him the modal (popup) again. I want to do that by cookie but my code does not work and I use cookie plugin to use JQuery Bootstarp Modal.
谢谢大家的帮助。
我的HTML代码
<!-- Modal -->
<div id="hereiakarneta" class="modal fade" role="dialog">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" id="AcceptMyGiftClose" data-dismiss="modal">×</button>
<h4 class="modal-title" style="text-align: center;" >From Me To You</h4>
</div>
<div class="modal-body">
<div class="hikmywords">
<img src="" class="img-responsive" alt="">
<ul>
<li><h5>my gift to you</h5></li>
<li>
<p>click on the button and download my gift</p>
</li>
</ul>
</div>
</div>
<div class="modal-footer">
<p><a>My Gift</a></p>
</div>
</div>
</div>
</div>
我的JQuery代码
jQuery(document).ready(function($) {
var VisitPopupGift = $.cookie('AcceptMyGift');
if ( !$.cookie('AcceptMyGift') ) {
$('#hereiakarneta').modal({
show: true,
backdrop: 'static',
keyboard: false,
})
$("#AcceptMyGiftClose").click(function() {
VisitPopupGift = 1;
$.cookie('AcceptMyGiftOnce', VisitPopupGift, {
expires: 30,
path: '/',
});
$(".hereiakarneta").fadeOut('fast');
});
} else {
if ( VisitPopupGift < 5 ) {
$('#hereiakarneta').modal({
show: true,
backdrop: 'static',
keyboard: false,
})
$("#AcceptMyGiftClose").on("click",function(){
//VisitPopupGift++;
VisitPopupGift++;
$.cookie('AcceptMyGiftOnce', VisitPopupGift, {
expires: 30,
path: '/',
});
$(".hereiakarneta").fadeOut('fast');
});
}
}
});
由于我不熟悉JQuery,因此想到的是,设置一个计数器来计算每次点击,然后设置一个if else语句,在if语句中,例如,如果counter小于或等于3,则显示模态,否则将其关闭或隐藏。