# 在Tic Tac Toe游戏中确定获胜者时，如何避免重复？ （Java）

``````public String determineWinner() {
int countX = 0; // amount of X's in a row
int countO = 0; // amount of O's in a row

for (int y = 0; y <= 2; y++) { // for all horizontal rows
countX = 0;
countO = 0;
for (int x = 0; x <= 2; x++) { // loop through all x-coordinates
String value = this.field[x][y];
if (value.equals("X")) { // if the value at that coordinate equals "X", add 1 to the count
countX++;
}
if (value.equals("O")) { // same here
countO++;
}
}
if (countX == 3) { // if the count is 3 (thus 3 X's in a row), X has won
return "X wins";
}
if (countO == 3) { // same here
return "O wins";
}
}

// Same thing, but for all vertical columns
for (int x = 0; x <= 2; x++) {
countX = 0;
countO = 0;
for (int y = 0; y <= 2; y++) {
String value = this.field[x][y];
if (value.equals("X")) {
countX++;
}
if (value.equals("O")) {
countO++;
}
}
if (countX == 3) {
return "X wins";
}
if (countO == 3) {
return "O wins";
}
}

// Same thing, but for diagonal
countX = 0;
countO = 0;
for (int i = 0; i <= 2; i++) {
String value = this.field[i][i];
if (value.equals("X")) {
countX++;
}
if (value.equals("O")) {
countO++;
}
}
if (countX == 3) {
return "X wins";
}
if (countO == 3) {
return "O wins";
}

// Same thing, but for other diagonal
countX = 0;
countO = 0;
for (int i = 0; i <= 2; i++) {
String value = this.field[i][2-i];
if (value.equals("X")) {
countX++;
}
if (value.equals("O")) {
countO++;
}
}
if (countX == 3) {
return "X wins";
}
if (countO == 3) {
return "O wins";
}

if (this.getNumberOfMoves() == 9) { // if the number of moves equals 9, the game is over and it is a draw
return "draw";
}

return "game not finished";
}
``````