为什么在C中这种“ printf（）”的模棱两可的行为？

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I have intentionally forced printf() to print celsius as an int (Using %8d format specifier for it.) But Why this whole table (other than the first step) prints 0 and moreover why fahr is going to be 0.0 even there is no changes made to it.

I have used gcc compiler.

这是摄氏到华氏转换的代码：

#define LOWER 0.0F
#define UPPER 300.0F
#define STEP 20.0F

#include<stdio.h>

void main(){
    float celsius, fahr;
    printf("*Conversion from Celsius to Fahrenheit*\n");
    printf("Celsius Scale \t   Fahrenheit Scale\n");
    for(celsius = LOWER; celsius <= UPPER; celsius = celsius + STEP){
        fahr = (9.0f * celsius / 5.0f) + 32.0f; 
        printf("%8d\t\t%5.1f\n", celsius, fahr);
    }
}

下表是上述代码的输出：

*Conversion from Celsius to Fahrenheit*
Celsius Scale      Fahrenheit Scale
       0                  0.0
       0                  0.0
       0                  0.0
       0                  0.0
       0                  0.0
       0                  0.0
       0                  0.0
       0                  0.0
       0                  0.0
       0                  0.0
       0                  0.0
       0                  0.0
       0                  0.0
       0                  0.0
       0                  0.0
       0                  0.0
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