我无法在功能操作期间禁用按钮。如果我在单击按钮时将其禁用,则从外观上看它是禁用的,但它仍然可以工作(或更确切地说,它使单击排队)。
这是我正在测试的有效演示代码:
Add-Type -AssemblyName System.Windows.Forms
[System.Windows.Forms.Application]::EnableVisualStyles()
$Form = New-Object system.Windows.Forms.Form
$Form.ClientSize = '400,400'
$Form.text = "Form"
$Form.TopMost = $false
$Button1 = New-Object system.Windows.Forms.Button
$Button1.text = "button"
$Button1.width = 100
$Button1.height = 25
$Button1.enabled = $true
$Button1.location = New-Object System.Drawing.Point(214,59)
$Button1.Font = 'Microsoft Sans Serif,10'
$Form.controls.AddRange(@($Button1))
Function Test {
Write-Host "Clicked"
$Button1.Enabled = $false
Start-Sleep -Seconds 2
$Button1.Enabled = $true
}
$Button1.add_Click(
{
Test
}
)
[void]$Form.ShowDialog()
I have tried putting in [System.Windows.Forms.Application]::DoEvents()
and button1.Update()
in the function.
我尝试在初始功能中禁用按钮,然后在与按钮单击不同的单独功能中调用需要花费较长时间的部件,但该部件也不起作用。即:
Function DisableBtn1 {
$Button3.Enabled = $false
}
Function DoStuff {
Write-Host "Bt1 Clicked"
Start-Sleep -Seconds 2
$Button3.Enabled = $True
}
$Button1.add_Click(
{
DisableBtn3
DoStuff
}
)
在脚本运行时正确禁用GUI元素方面,我是否缺少明显的东西?
继续以上我的评论...
做这个简单的测试将显示我的意思:
只是不要使用启用线