尝试在没有cs50 GetString的情况下执行cs50。 做新功能时卡住了。
该代码是
#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>
void PrintName(char name);
{
printf("Your name is %c\n", name);
}
int main();
{
char fio[10];
printf("Hello, ");
scanf("%c", &fio);
PrintName(fio);
return 0;
}
接下来说：
hello-0.c:9:1: error: expected identifier or '(' { ^ hello-0.c:14:1: error: expected identifier or '(' { ^
可能是什么？
First things first, you have extra semi-colons: in front of
mainandPrintNamefunction. Remove them.Secondly, you created char array (aka string) and you
scanf-ed it wrong. If you want to get name as string (not as a char, as you did), you have to do it like this:Note that, as I am reading string, my format is
%s(note 9 in there to read up to 9 characters, because you have array of 10). Moreover, I pass the address of my char array (which is already an address). That's how you read a string. And printing it in function will be:where we pass
char[]to function and again print with%sformat