数组-偶数和奇数

目标:

    - Program that reads a list of integers 
    - Outputs whether the list contains all even numbers, odd numbers, or neither
    - Input begins with an integer indicating the number of integers that follow
    - Contains less than 20 ints

我的代码可以输出偶数和奇数,执行我的else语句“不偶数或奇数”时遇到麻烦。我将代码放入Xcode,它说我的循环函数(偶数,奇数)有错误。我注释了每个for循环中的第一个返回值,并解决了该问题,但是当我将其放入我学校的程序中时,它除外。

我的代码:

#include <iostream>
using namespace std;

// proto
bool IsArrayEven(int inputVals[], int numVals);
bool IsArrayOdd(int inputVals[], int numVals);


int main() {
int MAX_ELEMENTS = 20;
cin >> MAX_ELEMENTS;
int userVals[MAX_ELEMENTS];
int i;

// populating array
for(i = 0;i < MAX_ELEMENTS; ++i){
  cin >> userVals[i];
 }

if(IsArrayEven(userVals, MAX_ELEMENTS)){
    cout << "all even" << endl;
}else if(IsArrayOdd(userVals, MAX_ELEMENTS)){
    cout << "all odd" << endl;
}else{
    cout << "not even or odd" << endl;
}
return 0;
}

// function definition - EVENS
bool IsArrayEven(int inputVals[], int numVals){
 for(int i = 0; i < numVals; ++i){
  if(inputVals[i] % 2 != 0){
     return false;
  }
  else {
    return true; 
  }
}
 return 0;
}

// function definition - ODDS
bool IsArrayOdd(int inputVals[], int numVals){
 for(int i = 0; i < numVals; ++i){
  if(inputVals[i] % 2 == 0){
    return false;
  }
  else {
    return true;
    }
  }
    return 0;
 }
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