从子组件到父组件的提升状态

由 发布于 javascriptreactjsstate
 收藏

I have 2 child components: a Categories select and a Search input text and submit button. They both have their own state. I have to use those two components in a parent page. I need to know in which category I have to do the search and to achieve this I think I should lift the state, so that the parent will handle it.

基本上，我从子组件中删除了状态，并将其放置在父组件上，最终得到了这样的代码（简化的代码）：

export default ParentPage = () => {

  const [searchString, setSearchString] = useState("");
  const [category, setCategory] = useState(0);

  const onSearch = () => {
    // search for searchString in the selected category
  }

  return (
    <>
      <Categories category={category} setCategory={setCategory} />
      <Search searchString={searchString} setSearchString={setSearchString} onSearch={onSearch} />
    </>
  )
}

这是一个好方法吗？似乎有些冗长，是否有更紧凑的方法将state和setState传递给子组件？

评论
换位思考
换位思考

代替此：

<Categories category={category} setCategory={setCategory} />
<Search searchString={searchString} setSearchString={setSearchString} />

您还可以使用以下名称，因为您要保留与州相同的名称道具：

<Categories { category , setCategory } />
<Search { searchString , setSearchString } />
注意：但是，从提供的内容中我看不到提升状态的任何目的   代码，所以就什么也不能说了。
点赞
评论
Ula
Ula

嗨，我在这里准备了一个完整的例子。您需要使用回调将子状态从子状态传递到父状态，然后在父状态上接收子状态，然后将该状态发送给另一个子状态。

父组件

import React, {useEffect, useState} from 'react';
import Child from "./Child";
import Sibling from "../Sibling";

function CParent(props) {

    const [status, setStatus] = useState(false);

    function setOpeningValue(status) {
        console.log('From Child to Parent:' + status);
        setStatus(status);
    }
    return (
        <div>
            <Child setOpeningValue={setOpeningValue}/>
            <Sibling status={status}/>
        </div>
    );
}
export default CParent;

子组件

import React, {useEffect, useState} from 'react';

// Child to Parent communication
function Child(props) {
    const {setOpeningValue} = props;
    const [isOpen, setOpen] = useState(false);

    function clickHandler() {
        setOpen(!isOpen);
        setOpeningValue(`changes is ${!isOpen}`);
    }
    return (
        <div>
            <button onClick={clickHandler}>Open</button>
        </div>
    );
}
export default Child;

同级组件

import React, {useEffect, useState} from 'react';

function Sibling(props) {
    const {status} = props;
    const [isOpen, setOpen] = useState(false);

    return (
        <div>
            From Child to Parent to Another Child (Sibling) {status}
        </div>
    );
}
export default Sibling;
点赞
评论