Python列表迭代比其他列表

由 EVE发布于 2020-05-18 16:38:01

我有2个清单

lst1 = [1,2,3,4,5,6,7,8,9,10]
lst2 = ['a','b','c','d']

我想输出为

1 - a
2 - b
3 - c
4 - d
5 - a
6 - b
7 - c
8 - d
9 - a
10 - b

如何在python中实现？

2020-05-18 16:38:01

Use zip and itertools.cycle:

from itertools import cycle

lst1 = [1,2,3,4,5,6,7,8,9,10]
lst2 = ['a','b','c','d']

for x, y in zip(lst1, cycle(lst2)):
    print(f"{x} - {y}")

输出：

1 - a
2 - b
3 - c
4 - d
5 - a
6 - b
7 - c
8 - d
9 - a
10 - b

2020-05-18 16:38:01

如果lst1始终大于lst2，这将很容易

lst1 = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
lst2 = ['a', 'b', 'c', 'd']

for i in range(len(lst1)):
    j = i % len(lst2)
    print(lst1[i],' - ',lst2[j])

这家伙很懒，什么都没留下