反应：尝试登录时this.setState不是一个函数

用户登录后，我试图将我的应用重定向到“ home”。我确实有一个onSubmitSignin函数，该函数会评估登录凭据（来自页面上的临时数据库），然后运行onRouteChange函数，该函数应该将路线更改为“家”，但出现错误“ this.setState不是函数”。

新来的反应，肯定有一些我不明白的地方。任何见解将不胜感激，谢谢！

App.js代码：

const initialState = {
    route: 'signin',
    isSignedIn: false
}


class App extends Component {

constructor(props){
    super(props);
    this.state = initialState;
}

onRouteChange (route) {
    if (route === 'signout') {
        this.setState({initialState});
    } else if (route === 'home') {
        this.setState({isSignedIn: true})
    }
    this.setState({route: route}) 
}


render () {
const { isSignedIn } = this.state;


return ( 
 <div className="App">
<Navigation onRouteChange={this.onRouteChange} />
{isSignedIn ? <Account /> : <Signin onRouteChange={this.onRouteChange}/> }
</div>
);
}
}
export default App;

登录代码：

et database = {
  email: 'test@gmail.com',
  password: 'test'
}

class Signin extends React.Component {
constructor(props){
    super(props);
    this.state = {
        signInEmail: '',
        signInPassword: ''
    }

}


onEmailChange = (event) => {
  this.setState({signInEmail: event.target.value})
}

onPasswordChange = (event) => {
  this.setState({signInPassword: event.target.value})
}

onSubmitSignIn = (e) => {
  e.preventDefault();
  if (this.state.signInEmail === database.email && this.state.signInPassword === database.password) {
    this.props.onRouteChange('home');
  } else {
    return (this.props.onRouteChange('signout'));
  }
}

render () {

  return (
    <div className="form">
    <form>
    <div className="form-group">
      <label htmlFor="email">Email address</label>
      <input onChange ={this.onEmailChange} type="email" className="form-control" id="email" aria-describedby="emailHelp" placeholder="Enter email"/>
    </div>
    <div className="form-group">
      <label htmlFor="password">Password</label>
      <input onChange ={this.onPasswordChange} type="password" className="form-control" id="password" placeholder="Password"/>
    </div>
    <div className="signInButton">
    <button onClick={this.onSubmitSignIn} type="submit" className="btn btn-secondary">Sign in</button>
    </div>
  </form>
  </div>
  )
}

}

export default Signin;