我需要从线性整数列表（不能从0开始）开始进行“相等”切片，但是要满足以下要求：
- 最后的值（最大值）总是必须出现
- 间隔不得小于步长（最重要的是，在倒数第二个和最后一个值之间）
- 给定上述要点，某些间隔可能比该步骤高，并且这些间隔必须在结果列表之间平均放置
- 仅应使用标准库函数（无numpy）
一些例子：
with a list from
range(10)and step 2, the result should be one of the following:[0, 2, 5, 7, 9]
[0, 2, 4, 7, 9]with
range(21)and step 3:[0, 3, 7, 10, 14, 17, 20]with
range(1, 22)and step 3:[1, 4, 8, 11, 15, 18, 21]
现在我有类似的东西，显然不能正常工作：
def getSlices(l, s):
skipCount = (len(l) - 1) % s
divCount = int(len(l) / (skipCount + 1))
o = []
for delta, skip in enumerate(range(skipCount + 1)):
o.extend(l[skip * divCount + delta:(skip + 1) * divCount + delta:s])
return o
>>> getSlices(list(range(21)), 3)
[0, 3, 6, 8, 11, 14, 16, 19]
I know I could just cycle through all values, skip by correlating enumerate indexes and steps, and add a "delta" as soon as a new "portion" of the list is reached, but that doesn't seem the most performing solution.
