很抱歉,如果在这里已经回答了类似的问题,但是也许我不知道如何找到它。
我有一些看起来像这样的列表:
A1, A6 = [157, 157, 0], [407, 157, 0]
A2, A7 = [207, 157, 0], [457, 157, 0]
然后我使用另一个列表将它们分组:
A_LIST = [A1, A2, A3, A4, A5, A6, A7, A8, A9, AX]
现在,我想遍历“ A_LIST”,从其中的每个元素中取出第一个和第二个元素。我尝试了几种方法:
def between(x, val):
if val <= x <= val + 50:
return True
def check_pressed():
mouse_x, mouse_y = pygame.mouse.get_pos()
click = pygame.mouse.get_pressed()
if click != (0, 0, 0):
i = 0
for i in A_LIST:
if between(mouse_x, A_LIST[i][0]) is True and between(mouse_y, A_LIST[i][1]) is True:
This approach brings an error saying unexpected type
reffering to "i". I also tried this format:
A_LIST[i[0]]
, but then it said IndexError: list index out of range
. Let's say this problem is solved, then how could i "feed" this iteration with nested lists other than A_LIST
? Like, taking 10 such sets (B_LIST
, C_LIST
, etc...), putting them into yet another list over which I would iterate.
提前致谢!
这应该工作: