GETOPTS bash解析参数和参数

有没有一种方法可以用两个参数解析一个参数?

这是我的示例脚本。

#!/bin/bash
while getopts "p:t:" param; do
case $param in
     p) ping -c3 $OPTARG
     ;;
     t) traceroute -4 $OPTARG
     ;;
esac
done

如果我使用参数-p或-t运行脚本,则一切正常。

:~# ./test.sh -p 8.8.8.8
PING 8.8.8.8 (8.8.8.8) 56(84) bytes of data.
64 bytes from 8.8.8.8: icmp_seq=1 ttl=52 time=30.0 ms
64 bytes from 8.8.8.8: icmp_seq=2 ttl=52 time=29.9 ms
64 bytes from 8.8.8.8: icmp_seq=3 ttl=52 time=29.9 ms
:~# ./test.sh -t 8.8.8.8
traceroute to 8.8.8.8 (8.8.8.8), 30 hops max, 60 byte packets
 1  bbrouter (192.168.1.1)  1.302 ms  0.976 ms  0.769 ms
 2  100.68.0.1 (100.68.0.1)  14.142 ms  14.113 ms  15.740 ms

What i'm trying to aim is would it be possible to use a parameter -pt and just using one argument to be parsed. Something like this. :~# ./test.sh -pt 8.8.8.8