如何不保存通过fetch方法获取的数据？ Java脚本

I am trying to fetch data from my server as often as possible.
To do so, I use the fetch method inside an AnimationFrame.
However, this work pretty well the first 30 secondes, and then it began to lag. When I looked at the Inspector, I can see that at every fetch I perform, the data the browser received is saved in a Fetches folder... resulting in thousands of files. How can I delete the data stored in the Fetches folder?
Here the main code:

function fetch_from_server() {
    if (has_new_value) {

        let infos = new FormData();
        infos.append('x', player.x);
        infos.append('y', player.y);
        infos.append('csrfmiddlewaretoken', csrf.getAttribute('value'));

        return fetch(url_info, {
            method: 'POST',
            body: infos,
            credentials: 'same-origin',
        })
        .then(response => response.json())
        .then(json => {
            update_p(json);
        })
        .then(_ => {
            has_new_value = false;
            is_fetching = false;})
        .catch(error => console.log('Error:', error));      
    }
    else {
        return fetch(url_info)
        .then(response => response.json())
        .then(json => {
            update_p(json);
        })
        .then(is_fetching = false)
        .catch(error => console.log('Error:', error));
    };
};

// Update Loop
function update(timestamp) {
    if (!is_fetching) {
        delay = (timestamp - last_update_time); // milliseconds
        is_fetching = true
        my_fetch = fetch_from_server();
    }

    rAF = window.requestAnimationFrame(update);
};

我通过单击事件监听器请求了第一个AnimationFrame。 这只是一个在迷你游戏中的浏览器之间交换数据的简单项目。我只是想玩JavaScript，但被困在这里，却无所适从。

谢谢你们！

阿德·卡茨

PS：即使我经常使用StackOverflow，这也是我的第一篇文章，如果我不遵守某些标准，我深表歉意。