我在.bashrc文件中定义了一个函数
function test(){
echo "test function is run"
}
每当我尝试获取.bashrc文件的源文件以获取最近进行的一些更新时，我都注意到该功能实际上已经运行了两次。
[myusername@myserver:~]$ source ~/.bashrc
test function is run
test function is run
真烦人 我以为source命令只能加载功能。 为什么要运行它？ 以及如何避免呢？ 谢谢。
This is happening because you have existing code in your
.bashrc(or invoked from your.bashrc) that callstest. That might sound strange — why is it already calling a function you've just created? — but it's becausetestis also the name of a command that's built into Bash [link], and the existing code is trying to use that command. By overridingtestwith your function, you're tricking that later code into calling your function instead of the built-in command.To fix this, rename your function to something other than
test, so as not to interfere with that later code.