在C中串联字符串时，如何用一个空格更改换行符？

由少心怡发布于 2020-05-24 03:11:15

首先，我必须提到，作为一个初学者，我只是在学习C语言中的字符串。我想要做的是从用户那里获取2个字符串作为输入并将它们连接起来。所以这就是我所做的：

char firststring[40], secondstring[40];

printf ("Enter first string: ");
fgets (firststring, 40, stdin);
printf ("Enter second string: ");
fgets (secondstring, 40, stdin);

strcat(firststring, secondstring);
printf("%s", firststring);

问题是，当用户输入第一个字符串时，fgets也会读取换行符，因此输出如下所示：

Hello World

I tried to use puts instead of fgets and it worked well, but too many people said NOT to use that function. Then i found out that i can use strcspn after the first fgets to remove the newline character, but that didn't gave me the one space i want between the words. Desired output: Hello World What i got: HelloWorld

有什么建议怎么做？

nquas

2020-05-24 03:11:15

您可以按照以下方式进行

printf ("Enter first string: ");
fgets (firststring, 40, stdin);
printf ("Enter second string: ");
fgets (secondstring, 40, stdin);

size_t n = strcspn( firststring, "\n" );
firststring[n] = ' ';
strcpy( firststring + n + 1, secondstring );

只要firststring有足够的空间来附加存储在secondstring数组中的字符串。

这是一个示范节目

#include <stdio.h>
#include <string.h>

int main(void) 
{
    enum { N = 40 };
    char firststring[N], secondstring[N];

    printf( "Enter first string: " );
    fgets( firststring, N, stdin );

    printf( "Enter second string: " );
    fgets( secondstring, N, stdin );

    size_t n = strcspn( firststring, "\n" );
    firststring[n] = ' ';

    strcpy( firststring + n + 1, secondstring );

    puts( firststring );

    return 0;
}

它的输出可能看起来像

Enter first string: Hello
Enter second string: World!
Hello World!

A general approach to remove the new line character from a string entered by a call of fgets is the following

string[ strcspn( string, "\n" ) ] = '\0';

少心怡

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