用Python获取当前年份

You need to convert your age as int as python takes input as str. And also change the bYear to str to print it using +.

import datetime
today = datetime.datetime.now()
def bYear():
    age = int(input("How old are you: "))
    bYear = today.year - age
    print("Born in: " + str(bYear))
bYear()

尝试这个：

from datetime import datetime
year = datetime.now().year
print(year)

The only real problem in your code is that you're not converting the input (which is a string) to integer to do the operation you want afterwards. You must be getting a TypeError, right?

Just change this: age = input("How old are you: "), with this:

age = int(input("How old are you: "))

这可能是因为您没有将输入类型更改为int，而是将其保留为字符串，但是，我不确定。如果您提供了完整的堆栈跟踪信息，那就太好了。尝试这个：

import datetime
today = datetime.datetime.now()
def bYear():
    age = int(input("How old are you: "))
    bYear = today.year - age
    print("Born in: " + bYear)
bYear()

如果您希望代码不崩溃（如果有人输入的不是整数），请尝试以下操作：

import datetime
today = datetime.datetime.now()
def bYear():
    age = input("How old are you: ")
    if not age.isdigit():
        print("Invalid input!")
    else:
        age = int(age)
    bYear = today.year - age
    print("Born in: " + bYear)
bYear()