用Python获取当前年份

由 发布于 pythonpython-3.x
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import datetime
today = datetime.datetime.now()
def bYear():
    age = input("How old are you: ")
    bYear = today.year - age
    print("Born in: " + bYear)
bYear()

我几天前开始学习python。尝试一些“愚蠢”的东西，但我无法使此代码正常工作。 如果我尝试用以下方式打印年份：

print(today.year)

输出正确。 我在这里想念什么，有什么帮助吗？

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禁锢的誓言
禁锢的誓言

You need to convert your age as int as python takes input as str. And also change the bYear to str to print it using +.

import datetime
today = datetime.datetime.now()
def bYear():
    age = int(input("How old are you: "))
    bYear = today.year - age
    print("Born in: " + str(bYear))
bYear()
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wnihil
wnihil

尝试这个：

from datetime import datetime
year = datetime.now().year
print(year)
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Buck
Buck

The only real problem in your code is that you're not converting the input (which is a string) to integer to do the operation you want afterwards. You must be getting a TypeError, right?

Just change this: age = input("How old are you: "), with this:

age = int(input("How old are you: "))
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aut_id
aut_id

这可能是因为您没有将输入类型更改为int，而是将其保留为字符串，但是，我不确定。如果您提供了完整的堆栈跟踪信息，那就太好了。尝试这个：

import datetime
today = datetime.datetime.now()
def bYear():
    age = int(input("How old are you: "))
    bYear = today.year - age
    print("Born in: " + bYear)
bYear()

如果您希望代码不崩溃（如果有人输入的不是整数），请尝试以下操作：

import datetime
today = datetime.datetime.now()
def bYear():
    age = input("How old are you: ")
    if not age.isdigit():
        print("Invalid input!")
    else:
        age = int(age)
    bYear = today.year - age
    print("Born in: " + bYear)
bYear()
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