提问
运行此代码时：import java.awt.Color;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.RenderingHints;
import javax.swing.JButton;
import javax.swing.JLabel;
public class CustomButton extends JButton {
int width = 100;
int height = 50;
int radius = 10;
JLabel lab;
@Override
protected void paintComponent(Graphics g) {
Graphics2D g2 = (Graphics2D) g;
g2.setRenderingHint(RenderingHints.KEY_ANTIALIASING,
RenderingHints.VALUE_ANTIALIAS_ON);
g2.setColor(Color.ORANGE);
g2.fillRoundRect(0, 0, width, height, radius, radius);
g2.dispose();
super.paintComponent(g2);
super.paintComponent(g);
}
}
而我的另一堂课：
package custom.frame;
import java.awt.FlowLayout;
import javax.swing.JFrame;
import javax.swing.JPanel;
public class CustomFrame {
public static void main(String[] args) {
JFrame f = new JFrame();
f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
f.setLayout(new FlowLayout());
f.setSize(500,500);
f.setLocationRelativeTo(null);
JPanel pane = new JPanel();
pane.setBounds(0,0,500,500);
CustomButton btn = new CustomButton();
pane.add(btn);
f.add(btn);
f.setVisible(true);
}
}
我得到一个只有1个圆角边的规则矩形.请参见下图.
这是预期的功能吗？
如果没有,我该如何解决.
编辑
如果这样做,我可以获得2个圆角：
g2.fillRoundRect(0,0,50,50,7,7);
